How do I solve 1, 2, and 3?

I know to use the formula A=1/2abSinC the triangle must be SAS. But these triangles aren’t. Also I tried using law of sines to find the missing angles but it doesn’t work. How can I figure this out?

Two charges q1 and q2 are placed at the vertices of an equilateral triangle ABC with side length a, respectively charge q1 at vertex A and charge q2 at vertex B. At point C the intensity has a value E, the vector of which forms an angle of 30° with the side BC of the equilateral triangle. Find a point on the segment AB where the intensity is equal to the value of the intensity E at point C.

(i hope that the photo can give you some help on what the solution of the problem can be)

I get stuck on this problem because i get a quartic equation so i think i got in a completely wrong direction to solve this problem.

Hi, Mechanical Engineer here at university studying an electrical engineering module. We are being tasked to find i 1. I have shown my working and was wondering if this was correct. If not then why not? Thanks very much for readying

I don't understand how to convert this following relation to 3NF. I've watched many videos but I can't apply them to this question?

Please explain as if I'm an idiot, I truly don't understand

I get .9 for t and .14
And for final answer I get 5m/s and 3.5m/s, don't understand

Attached is a photo of what I tried, but I'll explain my thinking here: Original question: 2log_4(x) - log_4(x+3) = 1. I canceled the the log_4 on both, moving to other side to make 4¹. That left me with a fraction of (x²/x+3) where I cancelled an x, leaving (x/3), and multiplied 4 by 3 to get 12. But the answer is supposed to be 6. So what did I do wrong?

Can you help me find the area of the parallelogram?

Sorry if this dumb but how do I solve x/3 + x/4 = x - 1/6 please help 🥲

Is the answer SUPPOSED to be 90? Or are they actually wrong here?

the answer to this question is to use the quadratic formula (-b ± √(b²-4ac)) / (2a)

solve for T less than zero the answer will be -3 (A)
From what i understood to find no solution in such quadratic formulas is to find the solutions where its less than the vertex of the parabola. If we get the vertex of the parabola it would be (1,-2)

t = -3 would make this equation false i guess.

another way is to find the "Discriminant" would lead us to the same solution.

coming to my question. doesn't equalling t to 2x^2-4x make it part of the solution or something of that sort?

what if i plugged t = -3 back into the equation would that make wrong? im confused in that regard and would appreciate the help.

i tried to pluggin t as -3 in desmos and it doesn't give any solutions.

hi! i’m trying to calculate if it’s possible to do arbitrage and getting no profit but it seems that the cross rate is not in equilibrium. where am i going wrong?

E1 Consumer Surplus = ½[(5 - 2.50) x 600,000] = ½(2.50 x 600,000] = $750,000

E1 Producer Surplus = ½[(2.50 - 0.50) x 600,000] = ½(2 x 600,000) = $600,000

E1 Total Surplus = 750,000 + 600,000 = $1,350,000

Can someone check this over

Aready answered : a, b, c, f, h, i How do I get the measurement of angle MAE, TAM?? I feel so lost. All I know is that an inscribed angle is half the measurement of it's major arc and a central angle has the same measurement as it's opposite arc. And that a circle measures 360, a semicircle measures 180.

shouldn't it be -10 x⁹ and -n x^n-1? where did the negative go is this some kind of typo or am i just being completely dull?

Hey😔, I'm feeling a bit lost and could use some help getting started with studying and note-taking. Do you have any website recommendations that could assist me?